N_1=1440,\quad N_2=160,\quad V_1=220\ \text{V},\quad I_1=15\ \text{A}.

Rapporti dell’ideale
 \frac{V_2}{V_1}=\frac{N_2}{N_1},\qquad \frac{I_2}{I_1}=\frac{N_1}{N_2}.

Corrente al secondario
 I_2=I_1,\frac{N_1}{N_2}=15\cdot\frac{1440}{160}=15\cdot 9=135\ \text{A}.

(Facoltativo: verifica potenza)
 V_2=V_1\frac{N_2}{N_1}=220\cdot\frac{160}{1440}=\frac{220}{9}\approx 24{,}44\ \text{V},\quad P_1=V_1 I_1=3300\ \text{W},\ P_2=V_2 I_2\approx 24{,}44\cdot135\approx 3300\ \text{W}.